Electrostatic Potential Energy and Conservative Forces class 12– NCERT Concepts, Formulas & CBSE PYQs


1. Introduction to Electrostatic Potential Energy and Conservative Forces

  • Potential energy was previously introduced in Class XI in the context of spring and gravitational forces.
  • When an external force performs work to move a body against a force (like spring or gravitational force), that work is stored as the potential energy of the body.
  • If the external force is removed, the body moves, converting potential energy into kinetic energy while conserving their sum.
  • Forces that conserve the sum of kinetic and potential energies are called conservative forces.
  • Examples of conservative forces include spring force and gravitational force.
  • The Coulomb force between two stationary charges is also a conservative force, similar to gravitational force due to its inverse-square dependence on distance.
  • Electrostatic potential energy can be defined for a charge within an electrostatic field, analogous to the potential energy of a mass in a gravitational field.

2. Electrostatic Potential

  • To define electrostatic potential energy, imagine bringing a test charge (q) from point R to point P against the repulsive electrostatic force exerted by a charge Q (assuming Q, q > 0).
  • The test charge q is assumed to be very small to avoid disturbing the original charge configuration, or the charge Q is kept fixed by an unspecified force.
  • An external force (F_ext) is applied, just sufficient to counteract the repulsive electric force (F_ext = -F_E), ensuring the test charge moves with infinitesimally slow constant speed and no net force or acceleration.
  • In this scenario, the work done by the external force is the negative of the work done by the electric force and is entirely stored as potential energy of the charge q.
  • Work done by external forces in moving a charge q from R to P is denoted as W_RP. This work increases the potential energy by an amount equal to the potential energy difference between P and R.
  • Electric potential energy difference between two points is defined as the work required by an external force to move a charge q (without acceleration) from one point to another in an electric field.
  • A fundamental characteristic of a conservative force is that the work done by an electrostatic field in moving a charge between two points depends only on the initial and final positions, and is independent of the path taken. The concept of potential energy relies on this path-independence.
  • Actual value of potential energy is not physically significant; only the difference in potential energy is significant. An arbitrary constant can always be added to the potential energy at every point without changing the difference.
  • A convenient choice is to set the electrostatic potential energy to zero at infinity.
  • Potential energy of charge q at a point is the work done by the external force in bringing the charge q from infinity to that point.
  • Electrostatic Potential (V):
    • Defined as the work done per unit test charge.
    • It is independent of the test charge q and is characteristic of the electric field.
    • Potential difference (V_P - V_R) is the work done by an external force in bringing a unit positive charge from R to P.
    • If potential is chosen to be zero at infinity, then electrostatic potential (V) at a point is the work done by an external force in bringing a unit positive charge from infinity to that point (without acceleration).
    • Count Alessandro Volta (1745-1827) was an Italian physicist who established that "animal electricity" was also generated when any wet body was sandwiched between dissimilar metals, leading to the development of the first voltaic pile (battery).

3. Potential Due to a Point Charge and Electric Dipole

  • Potential due to a point charge Q at a distance r from the origin is given by: V(r) = Q / (4πε₀r). This formula holds for any sign of Q.
    • For Q < 0, V < 0, meaning work done by an external force per unit positive test charge from infinity to the point is negative. This is consistent with the choice of zero potential at infinity.
    • Variation of potential V (∝ 1/r) and electric field E (∝ 1/r²) with distance r for a point charge Q is depicted in Figure 2.4.
  • Potential due to an Electric Dipole:
    • An electric dipole consists of two charges +q and -q separated by a small distance 2a, with a dipole moment vector p (magnitude q × 2a, pointing from -q to q).
    • The electric potential due to a dipole at a point P (with position vector r relative to the dipole's center) depends on both the magnitude r and the angle (θ) between r and p.
    • The superposition principle applies to electrostatic potential, meaning the potential due to a dipole is the sum of potentials from its individual charges.
    • For distances much greater than the dipole size (r >> a), the electric potential of a dipole is approximately: V(r) = (1 / 4πε₀) * (p ⋅ r̂ / r²).
    • Contrasting features with a single charge potential:
      • Dipole potential depends on angle (θ) between r and p, not just r. It is axially symmetric about p.
      • Dipole potential falls off as 1/r² at large distances, compared to 1/r for a single charge.
    • On the dipole axis (θ = 0 or θ = π), the potential is V = ±p / (4πε₀r²).
    • In the equatorial plane (θ = π/2), the potential is zero.

4. Potential Due to a System of Charges

  • For a system of multiple charges (q₁, q₂, ..., qₙ) at different positions, the total potential V at a point P is the algebraic sum of the potentials due to the individual charges (superposition principle).
  • V = V₁ + V₂ + ... + Vₙ.
  • V = (1 / 4πε₀) * (q₁/r₁P + q₂/r₂P + ... + qₙ/rₙP).
  • For a continuous charge distribution, the total potential is found by integrating the contributions from small volume elements.
  • For a uniformly charged spherical shell:
    • Electric field outside the shell is as if the entire charge is concentrated at the center. So, V = q / (4πε₀r) for r ≥ R (outside or on the surface).
    • Electric field inside the shell is zero. This implies that the potential is constant inside the shell and equals its value at the surface: V = q / (4πε₀R) (inside).

5. Equipotential Surfaces

  • An equipotential surface is a surface where the potential (V) is constant at all points.
  • For a single point charge q, equipotential surfaces are concentric spherical surfaces centered at the charge.
  • The electric field (E) at every point is normal (perpendicular) to the equipotential surface passing through that point.
    • If E had a component along the surface, work would be done to move a test charge, contradicting the definition of an equipotential surface.
  • Equipotential surfaces offer an alternative visual representation to electric field lines.
  • For a uniform electric field (e.g., along the x-axis), equipotential surfaces are planes normal to the field lines (e.g., planes parallel to the y-z plane).
  • Relation between Electric Field and Potential:
    • Electric field (E) is in the direction where the potential decreases steepest.
    • Its magnitude is the change in potential per unit displacement normal to the equipotential surface at that point: |E| = -dV/dl.

6. Potential Energy of a System of Charges

  • Potential energy of a system of charges is the work done by an external agency in assembling the charges at their specific locations.
  • For a system of two charges q₁ and q₂:
    • No work is needed to bring the first charge (q₁) from infinity.
    • Work done to bring q₂ from infinity to its position (r₂) in the field of q₁ is q₂ times the potential at r₂ due to q₁.
    • The potential energy (U) of a system of two charges q₁ and q₂ separated by distance r₁₂ is: U = q₁q₂ / (4πε₀r₁₂).
    • This expression is independent of the order in which the charges are brought and the path taken due to the conservative nature of electrostatic force.
    • U is positive for like charges (repulsive force, positive work needed to bring them together) and negative for unlike charges (attractive force, negative work needed for the reverse path from infinity).
  • For a system of three charges q₁, q₂, q₃:
    • The total potential energy is the sum of the potential energies of all unique pairs: U = (1 / 4πε₀) * (q₁q₂/r₁₂ + q₁q₃/r₁₃ + q₂q₃/r₂₃).
    • This final expression for U is independent of the assembly process.
  • Potential Energy of a Single Charge in an External Field:
    • If a charge q is placed in an external electric field E (or external potential V), its potential energy is defined as the work done in bringing it from infinity to that point in the external field.
    • Potential energy of q at r in an external field = qV(r), where V(r) is the external potential at point r.
    • Electron volt (eV) is a unit of energy commonly used in atomic, nuclear, and particle physics. 1 eV = 1.6 × 10⁻¹⁹ J.
  • Potential Energy of a System of Two Charges in an External Field:
    • The total potential energy is the sum of the work done against the external field for each charge, plus the mutual interaction energy between the charges.
    • U = q₁V(r₁) + q₂V(r₂) + q₁q₂ / (4πε₀r₁₂).
  • Potential Energy of a Dipole in a Uniform External Field:
    • A dipole (p) in a uniform electric field (E) experiences a torque τ = p × E.
    • The potential energy U(θ) associated with an inclination θ of the dipole with respect to the field is given by: U = -p ⋅ E = -pE cosθ.
    • The choice of zero potential energy is often taken at θ = π/2 (where cos(π/2) = 0).

7. Electrostatics of Conductors

Conductors contain mobile charge carriers (e.g., free electrons in metals, positive/negative ions in electrolytes). In the static situation, they exhibit important properties:

  1. Inside a conductor, electrostatic field is zero. Free charges redistribute themselves until the net electric field inside is zero.
  2. At the surface of a charged conductor, electrostatic field must be normal to the surface at every point. If there were a tangential component, free charges would move.
  3. The interior of a conductor can have no excess charge in the static situation. Excess charge resides only on the surface, as dictated by Gauss's law.
  4. Electrostatic potential is constant throughout the volume of the conductor and has the same value on its surface. This is because no work is done moving a test charge within or on the surface of a conductor where E=0 or has no tangential component.
  5. Electric field at the surface of a charged conductor is given by: E = (σ / ε₀)n̂, where σ is the surface charge density and n̂ is the outward normal unit vector.
  6. Electrostatic shielding: The electric field inside a cavity within a conductor is zero, provided there are no charges placed inside the cavity. This shielding works only one way; charges inside the cavity are not shielded from the external field. This effect is used to protect sensitive instruments.

8. Dielectrics and Polarisation

  • Dielectrics are non-conducting substances with few or negligible charge carriers.
  • Unlike conductors, dielectrics do not fully cancel an external electric field within them. Instead, the external field induces dipole moments in the dielectric molecules.
  • This leads to net induced charges on the surface of the dielectric, which produce a field opposing the external field, thereby reducing the net field inside.
  • Types of molecules in dielectrics:
    • Non-polar molecules: Centers of positive and negative charges coincide, thus having no permanent dipole moment (e.g., O₂, H₂). In an external field, they develop an induced dipole moment as charges are displaced in opposite directions. The dielectric becomes polarised.
    • Polar molecules: Centers of positive and negative charges are naturally separated, resulting in a permanent dipole moment (e.g., HCl, H₂O). In the absence of an external field, these dipoles are randomly oriented, resulting in zero net dipole moment. When an external field is applied, they tend to align with the field, leading to a net dipole moment and polarisation.
  • Polarisation (P): The dipole moment per unit volume.
    • For linear isotropic dielectrics, P = ε₀χₑE, where χₑ is the electric susceptibility of the dielectric medium.
  • A uniformly polarised dielectric is equivalent to induced surface charge densities (±σ_p) on its surfaces normal to the field, with no volume charge density. The field produced by these induced charges opposes the external field.

9. Capacitors and Capacitance

  • A capacitor is a system comprising two conductors separated by an insulator.
  • The conductors typically hold equal and opposite charges (Q and -Q), with a potential difference V = V₁ - V₂ between them. Q is called the charge of the capacitor.
  • The electric field in the region between conductors is directly proportional to the charge Q.
  • The potential difference V is also proportional to Q.
  • Capacitance (C) is the constant ratio of charge to potential difference: C = Q/V.
  • Capacitance C is independent of Q or V.
  • C depends solely on the geometrical configuration (shape, size, separation) of the conductors and the nature of the insulator (dielectric) between them.
  • The SI unit of capacitance is the farad (F): 1 F = 1 coulomb volt⁻¹ (C V⁻¹).
  • A large capacitance means the capacitor can hold a large amount of charge Q at a relatively small potential difference V.
  • Dielectric strength: The maximum electric field a dielectric can withstand without breakdown of its insulating property. For air, it's about 3 × 10⁶ Vm⁻¹.
  • Practical units for capacitance are sub-multiples of Farad: 1 µF = 10⁻⁶ F, 1 nF = 10⁻⁹ F, 1 pF = 10⁻¹² F.
  • Capacitors are key elements in AC circuits.

10. The Parallel Plate Capacitor

  • Consists of two large, plane, parallel conducting plates separated by a small distance d.
  • Let A be the area of each plate and d be the separation, with d² << A.
  • With charges +Q and -Q (surface charge densities σ = Q/A and ) and vacuum between plates:
    • The electric field outside the plates is zero.
    • The electric field between the plates is uniform: E = σ/ε₀ = Q/(Aε₀). Its direction is from the positive to the negative plate.
    • The potential difference between the plates is V = Ed = Qd/(Aε₀).
    • The capacitance of a parallel plate capacitor in vacuum is: C₀ = ε₀A/d.
  • A Farad is a very large unit; for instance, a 1F capacitor with 1 cm plate separation would require plates approximately 30 km in length and breadth.

11. Effect of Dielectric on Capacitance

  • When a dielectric material fully occupies the space between the plates of a parallel plate capacitor:
    • The dielectric is polarised, creating induced surface charges (±σ_p).
    • The net electric field in the dielectric is reduced to E = (σ - σ_p) / ε₀.
    • For linear dielectrics, (σ - σ_p) is proportional to σ, written as (σ - σ_p) = σ/K, where K is the dielectric constant of the dielectric.
    • The potential difference becomes V = Ed = σd / (Kε₀) = Qd / (KAε₀).
    • The new capacitance C with the dielectric is: C = Q/V = Kε₀A/d.
    • The product ε = Kε₀ is called the permittivity of the medium.
    • The dielectric constant (K = ε/ε₀) is a dimensionless ratio. It is the factor by which the capacitance increases from its vacuum value when the dielectric is fully inserted.
    • K > 1 for all dielectrics.

12. Combination of Capacitors

Capacitors can be combined to achieve an effective capacitance.

  • Capacitors in Series:
    • When capacitors are connected in series, the charge (Q) on each capacitor is the same.
    • The total potential drop (V) across the combination is the sum of individual potential drops across each capacitor: V = V₁ + V₂ + ... + Vₙ.
    • The formula for the effective capacitance (C) of n capacitors in series is: 1/C = 1/C₁ + 1/C₂ + ... + 1/Cₙ.
  • Capacitors in Parallel:
    • When capacitors are connected in parallel, the potential difference (V) across all capacitors is the same.
    • The total charge (Q) stored by the combination is the sum of the charges on individual capacitors: Q = Q₁ + Q₂ + ... + Qₙ.
    • The formula for the effective capacitance (C) of n capacitors in parallel is: C = C₁ + C₂ + ... + Cₙ.

13. Energy Stored in a Capacitor

  • To charge a capacitor, work must be done externally to transfer charge from one conductor to the other against the potential difference.
  • This work done is stored as potential energy (U) in the capacitor.
  • The energy stored in a capacitor with capacitance C, charge Q, and potential V is given by several equivalent formulas: U = ½QV = ½CV² = ½Q²/C.
  • This stored energy is released when the capacitor discharges.
  • The potential energy can be viewed as stored in the electric field between the plates.
  • For a parallel plate capacitor, the energy stored is U = (½)ε₀E²Ad.
    • Since Ad is the volume between the plates, the energy density (u) (energy stored per unit volume) of an electric field is: u = (½)ε₀E². This result is general for any charge configuration.
  • When a charged capacitor is disconnected from its supply and connected to an uncharged identical capacitor, half of the initial electrostatic energy is lost. This energy is dissipated as heat and electromagnetic radiation during the transient current flow.

14. Key Concepts and Insights

  • Electrostatics deals with forces between charges at rest; external forces are implied to keep them at rest against Coulomb forces.
  • Capacitors are designed to confine electric field lines to a small region, allowing a significant field strength while keeping the potential difference small.
  • Electric field is discontinuous across the surface of a charged spherical shell (zero inside, σ/ε₀ n̂ outside), but electric potential is continuous across the surface.
  • The torque on a dipole (p × E) causes it to oscillate; damping is required for it to eventually align with the field.
  • Potential due to a charge at its own location is undefined (infinite).
  • In the expression for potential energy qV(r), V(r) refers to the potential due to external charges only, not the potential due to the charge q itself.
  • Electrostatic shielding works by keeping the electric field inside a conductor's cavity zero from outside influences. However, if charges are placed inside the cavity, the exterior of the conductor is not shielded from their fields.

The behavior of these electric concepts can be imagined like water in a plumbing system. Electric potential is like the height of water in a tank – it's the "pressure" that drives the flow. Potential energy is the energy stored in the water due to its height, ready to do work as it falls. A capacitor is like a flexible tank that can store a lot of water (charge) at a certain height (potential). Connecting capacitors in series is like stacking tanks one on top of another; the total height increases, but the flow rate through each is the same. Connecting them in parallel is like connecting tanks side-by-side; the total capacity increases, and they all share the same height. And when a dielectric is added, it's like using a more elastic material for the tank, allowing it to expand and hold even more water at the same pressure.

Summary:

I. Electrostatic Potential Energy and Conservative Forces

  • Potential energy is introduced as work done by an external force in moving a body against a conservative force, such as spring force or gravitational force. This work is stored as potential energy.
  • When the external force is removed, the body gains kinetic energy and loses an equal amount of potential energy, indicating that the sum of kinetic and potential energies is conserved.
  • Conservative forces are those for which the sum of kinetic and potential energies is conserved. Examples include spring force, gravitational force, and Coulomb force between stationary charges.
  • The Coulomb force is a conservative force, similar to gravitational force, as both have an inverse-square dependence on distance.
  • Electrostatic potential energy of a charge in an electrostatic field can be defined, analogous to gravitational potential energy.
  • To bring a test charge q from point R to point P against a repulsive electric force, an external force (F_ext) is applied equal and opposite to the electric force (F_E = -F_ext). This ensures no net force or acceleration, meaning the charge is moved with infinitesimally slow constant speed.
  • In this scenario, the work done by the external force is the negative of the work done by the electric force and is fully stored as potential energy of the charge.
  • Potential energy difference (ΔU) between two points P and R is defined as the work done (W_RP) by the external force in moving a charge q from R to P: ΔU = U_P - U_R = W_RP.
  • The work done by an electrostatic field in moving a charge depends only on the initial and final points and is independent of the path taken. This path-independence is a fundamental characteristic of a conservative force and makes the concept of potential energy meaningful.
  • Actual potential energy values are not physically significant; only the potential energy difference is significant. An arbitrary constant can always be added to the potential energy at every point without changing the difference.
  • A convenient choice for defining potential energy is to set electrostatic potential energy to zero at infinity.
  • With this choice, the potential energy of charge q at a point is defined as the work done by the external force in bringing the charge q from infinity to that point.

II. Electrostatic Potential (Voltage)

  • Electrostatic potential (V) is derived by dividing the work done on a test charge q by the amount of charge q, making the quantity independent of q and characteristic of the electric field.
  • Potential difference (V_P - V_R) is defined as the work done by an external force in bringing a unit positive charge from point R to P: V_P - V_R = (U_P - U_R) / q.
  • Similar to potential energy, only the potential difference is physically significant, not the actual value of potential.
  • If potential is chosen to be zero at infinity, then the electrostatic potential (V) at any point is the work done in bringing a unit positive charge (without acceleration) from infinity to that point.
  • To accurately obtain work done per unit test charge, one should consider an infinitesimal test charge dq, find the work dW, and determine the ratio dW/dq.

III. Potential Due to Different Charge Configurations

  1. Potential Due to a Point Charge (Q)

    • For a point charge Q placed at the origin, the potential V(r) at any point P with position vector r is given by: V(r) = Q / (4πε₀r).
    • If Q < 0, V < 0, meaning work done by external force per unit positive test charge is negative. This aligns with the attractive electrostatic force in such a case.
    • The electrostatic potential V varies inversely with distance (1/r), while the electrostatic field E varies inversely with the square of the distance (1/r²).
  2. Potential Due to an Electric Dipole

    • An electric dipole consists of two charges q and -q separated by a small distance 2a, characterized by a dipole moment vector p = q × 2a pointing from -q to q.
    • The electric field of a dipole falls off as 1/r³ at large distances, unlike the 1/r² dependence of a single charge.
    • Due to the superposition principle, the potential due to a dipole is the algebraic sum of potentials due to its individual charges.
    • For distances r much greater than a (r >> a), the electric potential V of a dipole is given by: V(r) = (1 / 4πε₀) * (p.r̂ / r²).
    • Key contrasting features compared to a single charge:
      • The potential due to a dipole depends not only on r but also on the angle (θ) between the position vector r and the dipole moment vector p. It is axially symmetric about p.
      • The electric dipole potential falls off as 1/r² at large distances, unlike the 1/r characteristic of a single charge.
    • Potential on the dipole axis (θ = 0 or θ = π) is V = ±p / (4πε₀r²).
    • The potential in the equatorial plane (θ = π/2) is zero.
  3. Potential Due to a System of Charges

    • For a system of multiple point charges (q₁, q₂,..., q_n), the total potential V at any point P is the algebraic sum of the potentials due to the individual charges (superposition principle).
    • V = V₁ + V₂ + ... + V_n.
    • For a continuous charge distribution, the potential is found by integrating contributions from small volume elements.
    • For a uniformly charged spherical shell:
      • Outside the shell (r ≥ R), the potential is as if the entire charge q is concentrated at the center: V = q / (4πε₀r).
      • Inside the shell (r < R), the electric field is zero, which implies the potential is constant and equal to its value at the surface: V = q / (4πε₀R).

IV. Equipotential Surfaces

  • An equipotential surface is a surface where the potential is constant at all points.
  • For a single point charge, equipotential surfaces are concentric spherical surfaces centered at the charge.
  • A crucial property: the electric field E at every point is normal (perpendicular) to the equipotential surface passing through that point. If E had a tangential component, work would be required to move a charge along the surface, contradicting the definition of an equipotential surface.
  • The electric field is in the direction in which the potential decreases steepest.
  • The magnitude of the electric field |E| is given by the change in potential per unit displacement normal to the equipotential surface: |E| = -dV/dl.
  • For a uniform electric field, equipotential surfaces are planes normal to the field direction.

V. Potential Energy of a System of Charges (Self-Interaction)

  • The potential energy stored in a system of charges is defined as the work done by an external agency in assembling the charges at their given locations from infinity.
  • For a system of two charges q₁ and q₂:
    • The work done to bring q₁ is zero (no external field).
    • The work done to bring q₂ is q₂ times the potential at r₂ due to q₁.
    • The potential energy U of the system is U = q₁q₂ / (4πε₀r₁₂) where r₁₂ is the distance between them.
    • If q₁q₂ > 0 (like charges), U is positive, indicating positive work is needed against repulsion to bring them together.
    • If q₁q₂ < 0 (unlike charges), U is negative, indicating work is done by the attractive electrostatic force.
  • For a system of three charges q₁, q₂, q₃:
    • The total potential energy U is the sum of the potential energies of all unique pairs: U = (1 / 4πε₀) * (q₁q₂/r₁₂ + q₁q₃/r₁₃ + q₂q₃/r₂₃).
  • The final expression for potential energy is independent of the order in which the charges are assembled due to the conservative nature of the electrostatic force.

VI. Potential Energy in an External Field

  • This section addresses the potential energy of a charge (or system of charges) in an external field, where the field sources are external and not produced by the charge(s) in question.
  • Potential energy of a single charge q in an external potential V(r) is qV(r).
    • The electron volt (eV) is a common unit of energy in atomic and nuclear physics: 1 eV = 1.6 × 10⁻¹⁹ J.
  • Potential energy of a system of two charges (q₁ at r₁, q₂ at r₂) in an external field:
    • U = q₁V(r₁) + q₂V(r₂) + q₁q₂ / (4πε₀r₁₂). This includes energy due to interaction with the external field and mutual interaction between the charges.
  • Potential energy of a dipole (p) in a uniform external electric field E:
    • The dipole experiences a torque τ = p × E.
    • The potential energy U(θ) is given by U = -p.E. The zero potential energy is conventionally chosen when the dipole moment is perpendicular to the electric field (θ = π/2).

VII. Electrostatics of Conductors

  • Conductors contain mobile charge carriers (e.g., free electrons in metals, ions in electrolytes).
  • Key results regarding electrostatics of conductors in static situations:
    1. Inside a conductor, the electrostatic field is zero. Free charges redistribute until the field becomes zero everywhere inside.
    2. At the surface of a charged conductor, the electrostatic field must be normal to the surface at every point. This is because any tangential component would cause free charges to move.
    3. The interior of a conductor can have no excess charge; any excess charge resides only on the surface in static situations. This is a consequence of Gauss's Law and the zero field inside.
    4. Electrostatic potential is constant throughout the volume of the conductor and has the same value on its surface. No work is done in moving a test charge within or on the surface of a conductor.
    5. The electric field at the surface of a charged conductor is given by E = (σ/ε₀) n̂, where σ is the surface charge density and is the outward normal unit vector.
    6. Electrostatic shielding: The electric field inside a charge-free cavity within a conductor is zero, regardless of the cavity's shape or size, or external fields. This principle is used to protect sensitive instruments. Shielding works only from outside to inside, not vice-versa.

VIII. Dielectrics and Polarisation

  • Dielectrics are non-conducting substances with negligible charge carriers.
  • When a dielectric is placed in an external electric field, it does not fully cancel the field like a conductor but reduces it.
  • The external field induces dipole moments in the dielectric through polarisation.
  • Non-polar molecules have coincident centers of positive and negative charges; an external field displaces these centers, creating an induced dipole moment.
  • Polar molecules have inherent permanent dipole moments, which are randomly oriented in the absence of a field. An external field causes these permanent dipoles to tend to align with the field, resulting in a net dipole moment.
  • Polarisation (P) is the dipole moment per unit volume. For linear isotropic dielectrics, P = ε₀χ_e E, where χ_e is the electric susceptibility.
  • The uniform polarisation of a dielectric leads to induced surface charge densities (±σ_p) on its surfaces normal to the field. These induced charges produce a field that opposes the external field, thereby reducing the total field inside the dielectric. These are bound (not free) charges.

IX. Capacitors and Capacitance

  • A capacitor is a system of two conductors separated by an insulator (dielectric).
  • The conductors typically hold equal and opposite charges (+Q and -Q), with a potential difference V = V₁ - V₂ between them. The total charge of the capacitor is zero.
  • Capacitance (C) is defined as the ratio of the charge on one conductor to the potential difference between them: C = Q/V.
  • C is independent of Q or V; it depends only on the geometrical configuration (shape, size, separation) of the conductors and the nature of the insulator (dielectric) between them.
  • The SI unit of capacitance is the Farad (F), where 1 F = 1 Coulomb/Volt (C V⁻¹).
  • A capacitor with large capacitance can hold a large amount of charge Q at a relatively small potential difference V. This is important because high potential differences can lead to strong electric fields that ionize the surrounding air and cause charge leakage.
  • Dielectric strength is the maximum electric field a dielectric medium can withstand without breakdown.
  • The Farad (F) is a very large unit in practice; common units are microfarads (μF), nanofarads (nF), and picofarads (pF).
  • Parallel Plate Capacitor (with vacuum between plates):
    • Consists of two large parallel conducting plates of area A separated by a small distance d.
    • The electric field E between the plates is uniform and given by E = σ/ε₀ = Q/(Aε₀).
    • The potential difference V is V = E_0 d = Qd / (Aε₀).
    • The capacitance C is given by: C = ε₀A/d.

X. Effect of Dielectric on Capacitance

  • When a dielectric is inserted fully between the plates of a capacitor, the capacitance increases.
  • The dielectric is polarized by the field, creating induced surface charges ±σ_p.
  • The net electric field inside the dielectric becomes E = (σ - σ_p) / ε₀, which is less than E₀ (the field without dielectric).
  • The potential difference across the plates is reduced (V = E d), but the charge Q remains the same (if disconnected from source) or is increased (if connected to source).
  • The relationship is (σ - σ_p) = σ/K, where K is the dielectric constant of the material.
  • The new capacitance C with the dielectric is given by: C = K * (ε₀A/d) = KC₀.
  • The product ε₀K is called the permittivity of the medium (ε = ε₀K).
  • The dielectric constant K is a dimensionless ratio K = ε/ε₀. K > 1.
  • K is the factor by which the capacitance increases when the dielectric is inserted.

XI. Combination of Capacitors

  1. Capacitors in Series

    • When capacitors are connected in series (Fig. 2.26), the charge Q on each capacitor is the same.
    • The total potential drop V across the combination is the sum of the potential drops across individual capacitors: V = V₁ + V₂ + ... + V_n.
    • The formula for the effective capacitance C of n capacitors in series is: 1/C = 1/C₁ + 1/C₂ + ... + 1/C_n.
  2. Capacitors in Parallel

    • When capacitors are connected in parallel (Fig. 2.28), the same potential difference V is applied across all capacitors.
    • The total charge Q of the equivalent capacitor is the sum of the charges on individual capacitors: Q = Q₁ + Q₂ + ... + Q_n.
    • The formula for the effective capacitance C of n capacitors in parallel is: C = C₁ + C₂ + ... + C_n.

XII. Energy Stored in a Capacitor

  • A capacitor stores energy in its electric field.
  • The energy U stored in a capacitor of capacitance C with charge Q and voltage V can be expressed in several equivalent ways:
    • U = (1/2)QV
    • U = (1/2)CV²
    • U = (1/2)Q²/C
  • This stored energy is the work done by an external agency in charging the capacitor. It is independent of the charging process.
  • The energy density u (energy stored per unit volume) in a region with an electric field E is given by: u = (1/2)ε₀E². This result is general, not just for parallel plate capacitors.
  • When a charged capacitor is connected to an uncharged capacitor, energy can be lost during the transient period as heat and electromagnetic radiation.

XIII. Important Clarifications / Points to Ponder

  • In electrostatics, when discussing forces on charges at rest, it's implied that other unspecified forces are present to oppose the net Coulomb force, keeping the charges static.
  • Capacitors are designed to confine electric field lines to a small region, allowing for significant field strength with a relatively small potential difference.
  • The electric field is discontinuous across the surface of a charged conducting shell (zero inside, σ/ε₀ n̂ outside), but the electric potential is continuous across the surface.
  • A dipole in an electric field experiences a torque that tends to align it with the field. Without a dissipative mechanism, it would oscillate; dissipation damps oscillations and leads to alignment.
  • The potential due to a charge q at its own location is not defined (it is infinite).
  • In the expression qV(r) for potential energy, V(r) specifically refers to the potential due to external charges, not the potential generated by the charge q itself.
  • Electrostatic shielding works in one direction only: it shields the inside of a conductor's cavity from outside electrical influences. However, charges placed inside the cavity are not shielded from the exterior of the conductor.

Here is a detailed conceptual breakdown of Chapter 2 – Electrostatic Potential and Capacitance from Class 12 CBSE Physics.


📘 Chapter 2: Electrostatic Potential and Capacitance


🔑 Key Concepts

  1. Electrostatic Potential

    • Work done per unit charge in bringing a test charge from infinity to that point:

      V=WqV = \frac{W}{q}
  2. Potential due to:

    • A point charge:

      V=kQrV = \frac{kQ}{r}
    • A system of charges: Algebraic sum of potentials

    • An electric dipole at a point:

      V=14πε0pcosθr2V = \frac{1}{4\pi\varepsilon_0} \cdot \frac{p\cos\theta}{r^2}
  3. Equipotential Surfaces

    • Surface where potential is constant

    • Always perpendicular to electric field lines

  4. Electric Field and Potential Relation

    E=VorE=dVdr\vec{E} = -\nabla V \quad \text{or} \quad E = -\frac{dV}{dr}
  5. Potential Energy of:

    • System of two charges:

      U=14πε0q1q2rU = \frac{1}{4\pi\varepsilon_0} \cdot \frac{q_1q_2}{r}
    • Dipole in external field:

      U=pEU = -\vec{p} \cdot \vec{E}
  6. Capacitor

    • Device to store electrical energy

    • Capacitance:

      C=QVC = \frac{Q}{V}
  7. Parallel Plate Capacitor

    C=ε0Ad(without dielectric),C=Kε0Ad(with dielectric)C = \frac{\varepsilon_0 A}{d} \quad \text{(without dielectric)} \quad , \quad C = \frac{K\varepsilon_0 A}{d} \quad \text{(with dielectric)}
  8. Effect of Dielectric

    • Increases capacitance by factor K (dielectric constant)

  9. Combination of Capacitors

    • In Series:

      1Ceq=1C1+1C2+\frac{1}{C_\text{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \cdots
    • In Parallel:

      Ceq=C1+C2+C_\text{eq} = C_1 + C_2 + \cdots
  10. Energy Stored in a Capacitor

    U=12CV2=Q22C=12QVU = \frac{1}{2}CV^2 = \frac{Q^2}{2C} = \frac{1}{2}QV
  11. Van de Graaff Generator

    • Device to develop high voltage

    • Uses electrostatic induction and action of points


🔢 Important Formulas

Concept Formula
Electrostatic Potential V=WqV = \frac{W}{q}, V=kQrV = \frac{kQ}{r}
Electric Field from Potential E=dVdrE = -\frac{dV}{dr}
Capacitance C=QVC = \frac{Q}{V}
Parallel Plate Capacitor C=ε0AdC = \frac{\varepsilon_0 A}{d}
Energy Stored U=12CV2U = \frac{1}{2}CV^2
Series Combination 1C=1Ci\frac{1}{C} = \sum \frac{1}{C_i}
Parallel Combination C=CiC = \sum C_i

🔍 Applications

  • Calculating work done in electrostatics

  • Designing capacitors with required capacitance

  • Using capacitors in circuits for energy storage

  • High-voltage generation in physics experiments (Van de Graaff)


📘 NCERT Exercise Questions with Solutions (Class 12 Physics Chapter 2)


Q1. Two charges 5×108C5 \times 10^{-8} \, \text{C} and 3×108C -3 \times 10^{-8} \, \text{C} are located 16 cm apart. At what point on the line joining them is the electric potential zero?

Solution:
Let the point be at a distance xx from the 5 µC charge where potential is zero.
Apply:

k5×108x=k3×10816x\frac{k \cdot 5 \times 10^{-8}}{x} = \frac{k \cdot 3 \times 10^{-8}}{16 - x}

Solving:

5x=316x5(16x)=3xx=10cm\frac{5}{x} = \frac{3}{16 - x} \Rightarrow 5(16 - x) = 3x \Rightarrow x = 10 \, \text{cm}

Answer: 10 cm from the 5 μC charge.


Q2. A regular hexagon of side 10 cm has a charge 5 μC at each vertex. Find the potential at the center.

Solution:
All distances from center to each vertex are equal. So total potential:

V=6kqrV = 6 \cdot \frac{k \cdot q}{r}

Where r=10cm=0.1mr = 10 \, \text{cm} = 0.1 \, \text{m}, q=5×106q = 5 \times 10^{-6}

V=69×1095×1060.1=2.7×106VV = 6 \cdot \frac{9 \times 10^9 \cdot 5 \times 10^{-6}}{0.1} = 2.7 \times 10^6 \, \text{V}


Q3. Two charges 2 μC and –2 μC are placed at (0, 0) and (0, 6 cm). Find the potential at (0, 3 cm).

Solution:
The point is equidistant from both charges → net potential = 0
Answer: 0 V


Q4. A charge of 2 μC is placed at the center of a cube. What is the flux through one face?

Solution:
Total flux:

Φ=qε0=2×1068.85×10122.26×105Nm2/C\Phi = \frac{q}{\varepsilon_0} = \frac{2 \times 10^{-6}}{8.85 \times 10^{-12}} \approx 2.26 \times 10^5 \, \text{Nm}^2/\text{C}

Each face gets 1/6 of the flux:

Φface=16Φ3.77×104Nm2/C\Phi_{\text{face}} = \frac{1}{6} \cdot \Phi \approx 3.77 \times 10^4 \, \text{Nm}^2/\text{C}


Q5. Derive expression for potential due to electric dipole at axial and equatorial line.

Solution:

  • Axial line:

V=14πε02pr2V = \frac{1}{4\pi\varepsilon_0} \cdot \frac{2p}{r^2}

  • Equatorial line:

V=0(because contributions cancel out)V = 0 \quad \text{(because contributions cancel out)}


Q6. Derive expression for capacitance of parallel plate capacitor.

Solution:
Without dielectric:

C=ε0AdC = \frac{\varepsilon_0 A}{d}

With dielectric:

C=Kε0AdC = \frac{K\varepsilon_0 A}{d}


📋 CBSE Previous Year Questions (PYQs) with Best Answers


🔹 Q (2023)

Define electric potential. Draw equipotential surfaces for point charge.

Answer:
Electric potential at a point is the work done in bringing a unit positive charge from infinity to that point.
Equipotential surfaces are concentric spheres around the charge. No work is done when moving along them.


🔹 Q (2022)

Derive the expression for energy stored in a capacitor.

Answer:
Work done:

U=0QqCdq=12Q2CU = \int_0^Q \frac{q}{C} \, dq = \frac{1}{2} \cdot \frac{Q^2}{C}

Also expressed as:

U=12CV2=12QVU = \frac{1}{2}CV^2 = \frac{1}{2}QV


🔹 Q (2021)

Capacitors 6 μF and 12 μF in series with 12V. Find:

  • Equivalent capacitance:

    1C=16+112C=4μF\frac{1}{C} = \frac{1}{6} + \frac{1}{12} \Rightarrow C = 4 \, \mu F
  • Energy:

    U=124(12)2×106=2.88×104JU = \frac{1}{2} \cdot 4 \cdot (12)^2 \times 10^{-6} = 2.88 \times 10^{-4} \, \text{J}

🔹 Q (2020)

Explain Van de Graaff Generator.

Answer:

  • Works on electrostatic induction and action of points

  • Charge is transferred to a large conducting sphere via a moving belt

  • Used to generate high voltages (~10^7 V) for experiments like nuclear physics

  • Key parts: hollow sphere, belt, pulley, spray comb, discharge sphere

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