Class 10 Maths Chapter 3 – Pair of Linear Equations in Two Variables | NCERT Solutions & Board Questions (2025–26)

 Class 10 CBSE Maths – Chapter 3: Pair of Linear Equations in Two Variables


🔹 Key Concepts and Formulas

✅ Linear Equation in Two Variables:

An equation of the form:
ax+by+c=0ax + by + c = 0
Where a, b, c are real numbers, and a and b are not both zero.

✅ Solution of a Pair of Linear Equations:

A solution is a pair (x, y) that satisfies both equations simultaneously.

✅ Graphical Method:

  • Each equation represents a straight line.

  • The point of intersection gives the solution.

Types of Solutions:

  1. Consistent and Unique (Lines intersect at one point)

  2. Consistent and Infinite Solutions (Lines coincide)

  3. Inconsistent (Lines are parallel)

Condition Table:

Condition Type of Lines Number of Solutions
a1a2b1b2\frac{a_1}{a_2} \neq \frac{b_1}{b_2} Intersecting lines Unique solution
a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} Coincident lines Infinitely many
a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} Parallel lines No solution

✅ Algebraic Methods:

  1. Substitution Method

  2. Elimination Method

  3. Cross-Multiplication Method


📘 NCERT Solved Examples (Highlights)

Example 1:

Solve graphically:
x+y=5 and xy=1x + y = 5 \text{ and } x - y = 1
Solution: Solve for two points for each equation and plot. Intersection point is (3, 2).

Example 2:

Use elimination method:
2x+3y=12 and xy=12x + 3y = 12 \text{ and } x - y = 1
Multiply second equation by 3 and eliminate y.


🔹 📄 Exercise 3.1 – Graphical Method

Q1. Solve and represent graphically:

x+y=5andxy=1x + y = 5 \quad \text{and} \quad x - y = 1

  • Plot both equations.

  • Intersect at (3, 2)
    ✅ Solution: x=3,y=2x = 3, y = 2

Q2. Draw graphs and state solution type:

Check for parallel, intersecting, or coincident lines using condition table.


🔹 📄 Exercise 3.2 – Algebraic Method: Substitution

Q1. Solve using substitution:

x+y=14andxy=4x + y = 14 \quad \text{and} \quad x - y = 4

  • From first: x=14yx = 14 - y

  • Substitute in second:
    14yy=4y=514 - y - y = 4 \Rightarrow y = 5, then x=9x = 9
    ✅ Solution: (9, 5)


🔹 📄 Exercise 3.3 – Elimination Method

Q1. Solve:

3x+4y=10and2x2y=23x + 4y = 10 \quad \text{and} \quad 2x - 2y = 2

  • Multiply to make coefficients equal

  • Add/Subtract equations to eliminate one variable

  • Solve remaining linear equation
    ✅ Final Answer: x=2,y=1x = 2, y = 1


🔹 📄 Exercise 3.4 – Cross Multiplication Method

Q1. Solve:

2x+3y=17and4xy=52x + 3y = 17 \quad \text{and} \quad 4x - y = 5

  • Apply cross multiplication:
    x(b1c2b2c1)=y(c1a2c2a1)=1(a1b2a2b1)\frac{x}{(b_1c_2 - b_2c_1)} = \frac{y}{(c_1a_2 - c_2a_1)} = \frac{1}{(a_1b_2 - a_2b_1)}

  • Plug values, solve to get x and y
    ✅ Solution: (x, y)


🔹 📄 Exercise 3.5 – Applications (Word Problems)

Q1. The sum of the digits of a two-digit number is 9. If 27 is subtracted from the number, its digits are reversed. Find the number.

Let tens digit = x, unit digit = y

  • Number = 10x + y

  • Equation 1: x+y=9x + y = 9

  • Equation 2: 10x+y27=10y+x10x + y - 27 = 10y + x

  • Solve using substitution or elimination
    ✅ Answer: Number is 63


🔹 Summary and Revision Notes

  • Linear equations are straight-line equations in x and y

  • Algebraic methods are more accurate than graphical method

  • Always check type of solution using condition table

  • Use substitution for easy expressions, elimination when coefficients match

  • Word problems are modeled into linear systems and solved algebraically

Here’s a comprehensive list of past CBSE Board Exam Questions from Chapter 3: Pair of Linear Equations in Two Variables, arranged by marking scheme, updated for the 2025–26 exam pattern. These questions have appeared in actual board papers or official sample papers (2016–2024).


📘 CBSE Past Year Board Questions – Class 10 Maths Chapter 3: Pair of Linear Equations


1-MARK QUESTIONS

  1. (2020) Write the condition for a pair of linear equations to be inconsistent.
    📌 Answer:
    a1a2=b1b2c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}

  2. (2019) Find the value of k if the pair of equations has a unique solution:
    2x+3y=72x + 3y = 7
    (k1)x+(k+2)y=3(k - 1)x + (k + 2)y = 3
    📌 Answer: Use: 2k13k+2\frac{2}{k - 1} \neq \frac{3}{k + 2}

  3. (2021 – Sample) What type of pair of linear equations is represented by:
    3x+2y=63x + 2y = 6 and 6x+4y=126x + 4y = 12?
    📌 Answer:
    36=24=612\frac{3}{6} = \frac{2}{4} = \frac{6}{12} \Rightarrow Infinitely many solutions


2-MARK QUESTIONS

  1. (2020) Solve the pair of equations:
    5x3y=115x - 3y = 11,
    10x+6y=22-10x + 6y = -22
    📌 Answer: Use elimination. Multiply first equation by 2.

  2. (2017) If x=1,y=1x = 1, y = 1 is a solution of the pair 2x+3y=a2x + 3y = a and 4x+6y=b4x + 6y = b, find values of a and b.
    📌 Answer:
    Substituting:
    a=2+3=5a = 2 + 3 = 5, b=4+6=10b = 4 + 6 = 10


3-MARK QUESTIONS

  1. (2022) Solve by substitution:
    x+y=5x + y = 5,
    2x3y=42x - 3y = 4
    📌 Answer:
    From 1st: x=5yx = 5 - y, plug into 2nd:
    2(5y)3y=42(5 - y) - 3y = 4

  2. (2020) Solve:
    2x+3y=122x + 3y = 12,
    xy=1x - y = 1
    📌 Answer: Use elimination. Multiply second equation by 3.

  3. (2018) Find value of k for which the system has no solution:
    kx+3y=k3kx + 3y = k - 3,
    12x+ky=k12x + ky = k
    📌 Answer:
    Use condition: k12=3kk3k\frac{k}{12} = \frac{3}{k} \neq \frac{k - 3}{k}


4-MARK QUESTIONS

  1. (2019) Solve:
    3xy=33x - y = 3,
    9x3y=99x - 3y = 9
    📌 Answer:
    Check: 39=13=39\frac{3}{9} = \frac{-1}{-3} = \frac{3}{9} \Rightarrow Infinite solutions

  2. (2017) A boat goes 30 km downstream in 2 hours and 18 km upstream in 3 hours. Find speed of boat and current.
    📌 Answer:
    Let speed of boat = x, speed of stream = y
    Equations:
    30x+y=2\frac{30}{x + y} = 2,
    18xy=3\frac{18}{x - y} = 3


5-MARK WORD PROBLEMS

  1. (2024 – Sample Paper) The sum of two numbers is 100. If one number is twice the other decreased by 10, find the numbers.
    📌 Answer:
    Let numbers be x and y
    x+y=100x + y = 100,
    x=2y10x = 2y - 10

  2. (2020) A fraction becomes 12\frac{1}{2} when 1 is subtracted from the numerator, and becomes 13\frac{1}{3} when 1 is added to the denominator. Find the fraction.
    📌 Answer:
    Let fraction = xy\frac{x}{y},
    Equations:
    x1y=12\frac{x - 1}{y} = \frac{1}{2},
    xy+1=13\frac{x}{y + 1} = \frac{1}{3}

  3. (2016) The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 27 less than the original. Find the number.
    📌 Answer:
    Let tens digit = x, units = y
    Equations:
    x+y=9x + y = 9,
    10x+y27=10y+x10x + y - 27 = 10y + x


🔁 Frequently Tested Topics:

  • Graphical interpretation of solution types

  • Solving by substitution, elimination

  • Framing and solving word problems

  • Conditions for unique/no/infinite solutions

  • Forming equations from real-life contexts


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